How do I extract the url from sharing_get_shared_links?

Question

I am stuck in getting the url from sharing_get_shared_links?   Been trying all day with no success.  I had no issue with the create_link but that also returns a slew of data which it has the url but much more complex than the get_shared_link.

Help please, stuck in the mud.

shared_link_metadata = dbx.sharing_get_shared_links(path=save_product_path) shared_link_metadata contains:GetSharedLinksResult(links=[PathLinkMetadata(expires=NOT_SET, path='/Test_App/Beach Vibes (GO)/Beach Vibes - 6x8 - GO WEB.jpg',url='https://www.dropbox.com/s/pexagwz8il76t1k/Beach%20Vibes%20-%206x8%20-%20GO%20WEB.jpg?dl=0', visibility=Visibility('public', None))])

babydream · Accepted Answer

I am using Python 3.11.   I finally figured out how to get to the url through trial and error.  Dropbox documentation on Python needs to be updated to explicitly state how the return values are processed.  Otherwise, it can be a nightmare.  I know you guys don't support language specifics on how to extract the parameter values but it would be nice to have this documented.  Thank you

shared_link_metadata = sharing_get_shared_links(path=save_product_path)
        iterator = iter(shared_link_metadata.links)        print(iterator)        for item in iterator:            shared_link = item.url